2[d+3(d-1)]=18

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Solution for 2[d+3(d-1)]=18 equation:


Simplifying
2[d + 3(d + -1)] = 18

Reorder the terms:
2[d + 3(-1 + d)] = 18
2[d + (-1 * 3 + d * 3)] = 18
2[d + (-3 + 3d)] = 18

Reorder the terms:
2[-3 + d + 3d] = 18

Combine like terms: d + 3d = 4d
2[-3 + 4d] = 18
[-3 * 2 + 4d * 2] = 18
[-6 + 8d] = 18

Solving
-6 + 8d = 18

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 8d = 18 + 6

Combine like terms: -6 + 6 = 0
0 + 8d = 18 + 6
8d = 18 + 6

Combine like terms: 18 + 6 = 24
8d = 24

Divide each side by '8'.
d = 3

Simplifying
d = 3

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